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Paper 4 (9164, Section A) · June 2011 · Binomial and Geometric Distributions

A discrete random variable Y follows a geometric distribution with variance 12. Find the probability of success on a single trial.

Model answer

1/4

Also accepted: 0,25, 0.25, p=1/4, p = 0,25, 0,250, 0.250

Explanation

A geometric distribution with success probability pp has variance 1−pp2\dfrac{1-p}{p^{2}}. Setting 1−pp2=12\dfrac{1-p}{p^{2}}=12 gives 12p2+p−1=012p^{2}+p-1=0, that is (4p−1)(3p+1)=0(4p-1)(3p+1)=0. A probability cannot be negative, so p=14p=\dfrac{1}{4}.

Derived from ZIMSEC Statistics Paper 4, June 2011, Q1

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