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Paper 2 · November 2019 · Descriptive Statistics

In a survey of 100 athletes at a marathon, the amount of water taken, in litres, was recorded as: 0-0.5 litres by 8 athletes, 0.5-1.0 litres by 20 athletes, 1.0-1.5 litres by 29 athletes, 1.5-2.0 litres by 22 athletes, and 2.0-2.5 litres by 21 athletes. Using the midpoint of each class and a mean of 1.39 litres, what is the estimated standard deviation of the amount of water taken, correct to 3 decimal places?

Model answer

0.613

Also accepted: 0.61

Explanation

∑fx2=230.75\sum fx^2 = 230.75, so variance =230.75100−1.392=2.3075−1.9321=0.3754= \frac{230.75}{100} - 1.39^2 = 2.3075 - 1.9321 = 0.3754, giving SD =0.3754≈0.613= \sqrt{0.3754} \approx 0.613 litres.

Derived from ZIMSEC Statistics Paper 2, November 2019, Q2

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