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Paper 2 · Specimen 2026 · Continuous Random Variables

A continuous random variable XX has probability density function f(x)=0.1x−0.3f(x) = 0.1x - 0.3 for 4≤x≤64 \leq x \leq 6, f(x)=0.3f(x) = 0.3 for 6≤x≤86 \leq x \leq 8, and f(x)=0f(x) = 0 otherwise. Find P(5≤X≤7)P(5 \leq X \leq 7).

Model answer

0.55

Also accepted: 0,55, 11/20

Explanation

P(5≤X≤7)=∫56(0.1x−0.3) dx+∫670.3 dxP(5 \leq X \leq 7) = \int_5^6 (0.1x-0.3)\,dx + \int_6^7 0.3\,dx. The first part is 0.05(62−52)−0.3=0.55−0.3=0.250.05(6^2-5^2) - 0.3 = 0.55 - 0.3 = 0.25 and the second is 0.30.3, giving 0.25+0.3=0.550.25 + 0.3 = 0.55.

Derived from ZIMSEC Statistics 6046/2 Paper 2, Specimen Paper, Q1

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