A company receives on average 6 orders per day, following a Poisson distribution. What is the probability that no more than 2 orders will be received on a given day, to 3 decimal places?

A0.045

B0.062

C0.089

D0.120

Explanation

With X ~ Poisson(6), P(X <= 2) = P(0)+P(1)+P(2) = e^-6(1+6+18) = 25e^-6, which is approximately 0.062.

Derived from ZIMSEC Statistics Paper 2, November 2018, Q8

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