An alternating current with the wave form and magnitude shown in the diagram passes through a milliameter calibrated for r.m.s. readings of current. What current, in mA, will the meter record?

5\sqrt{2}

C10

10\sqrt{2}

Explanation: For a sinusoidal current with peak value 10mA, the r.m.s. value = peak/√2 = 10/√2 = 5√2 mA. Answer B.

ZIMSEC Physics Paper 1, November 2002, Q16

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