For $2H_2 + 2NO \rightarrow 2H_2O + N_2$ , doubling $[NO]$ at constant $[H_2]$ raised the rate from 0.024 to $0.096\ mol\,dm^{-3}\,s^{-1}$ . The order of reaction with respect to NO is

Explanation: The rate increased four-fold when the concentration was doubled, and

2^2 = 4

Derived from ZIMSEC Chemistry Paper 2, November 2008, Q2

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