2.000 g of lead was converted completely into lead(II) chloride, giving 2.682 g of the chloride. Taking $A_r(Cl) = 35.45$ , the relative atomic mass of the lead is

A103.9

B207.9

C311.8

D415.8

Explanation

Mass of chlorine = 0.682 g, so moles of Cl = 0.0192.

PbCl_2

needs 2 Cl per Pb, so moles of Pb = 0.00962 and

A_r = 2.000/0.00962 = 207.9

Derived from ZIMSEC Chemistry Paper 2, November 2003, Q1

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