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Paper 1 · November 2010 · Vectors

The position vectors of the points AA, BB and CC relative to the origin OO are a=3i−ja = 3i - j, b=2i+j+3kb = 2i + j + 3k and c=i−j+6kc = i - j + 6k. Find the value of a⋅(b×c)a \cdot (b \times c).

Model answer

36

Also accepted: +36

Explanation

a⋅(b×c)a\cdot(b\times c) is the determinant whose rows are (3,−1,0)(3,-1,0), (2,1,3)(2,1,3) and (1,−1,6)(1,-1,6). Expanding along the top row, 3(1(6)−3(−1))+1(2(6)−3(1))+0=3(9)+1(9)=363\big(1(6)-3(-1)\big)+1\big(2(6)-3(1)\big)+0 = 3(9)+1(9) = 36.

Derived from ZIMSEC Further Mathematics 9187/1, November 2010, Q1

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