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ZIMSEC A Level · 9164/4 · J2013

Mechanics Paper 4 June 2013

Questions
10
Total marks
24
Syllabus code
9164/4

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Questions
10
Pass mark
6
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Answer every question in the printed order, get marked at the end, then see the answers.

The questions

Section b

Section b, Question 6

[2 marks]Friction on an inclined plane

A particle of mass 8 kg rests on a rough plane inclined at 30∘^{\circ} to the horizontal and is on the point of slipping. Take g=9.81g = 9.81 ms−2^{-2}.

Calculate the component of the particle's weight acting down the line of greatest slope, in newtons.

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[2 marks]Friction on an inclined plane

A particle of mass 8 kg rests on a rough plane inclined at 30∘^{\circ} to the horizontal and is on the point of slipping. Take g=9.81g = 9.81 ms−2^{-2}.

Calculate the coefficient of friction between the plane and the particle, giving your answer as a decimal.

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[3 marks]Projectiles
A ball is projected from a point O with speed uu ms−1^{-1} at an angle θ\theta above the horizontal, and air resistance is neglected. Which expression gives the time taken for the ball to travel a horizontal distance xx from O?
  1. Aucos⁡θx\dfrac{u\cos\theta}{x}
  2. Bxucos⁡θxu\cos\theta
  3. Cxucos⁡θ\dfrac{x}{u\cos\theta}
  4. Dxusin⁡θ\dfrac{x}{u\sin\theta}
[3 marks]Projectiles

A ball is thrown from a height of 0.9 m above the ground at an angle of 30∘^{\circ} to the horizontal. It is to clear a wall which stands 10,5 m away horizontally and is 4,5 m high. Air resistance is neglected and g=9.81g = 9.81 ms−2^{-2}.

The trajectory satisfies y=xtan⁡θ−gx2(1+tan⁡2θ)2u2y = x\tan\theta - \dfrac{gx^{2}\left(1+\tan^{2}\theta\right)}{2u^{2}}, where x and y are measured from the point of projection.

Find the least speed of projection, in ms−1^{-1}, for which the ball clears the wall.

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[2 marks]Resultant of coplanar forces

Coplanar forces of magnitudes 3 N, 4 N and 8 N act at a point as shown in the diagram. The 3 N force acts along the direction of j\mathbf{j}, the 4 N force acts along the direction of i\mathbf{i}, and the 8 N force acts at an angle θ\theta below the direction of −i-\mathbf{i}.

The resultant force in the i\mathbf{i} direction is 4(1−3)4\left(1-\sqrt{3}\right) N. Find θ\theta, in degrees.

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[3 marks]Resultant of coplanar forces

Coplanar forces of magnitudes 3 N, 4 N and 8 N act at a point as shown in the diagram. The 3 N force acts along the direction of j\mathbf{j}, the 4 N force acts along the direction of i\mathbf{i}, and the 8 N force acts at an angle θ\theta below the direction of −i-\mathbf{i}.

Given that θ=30∘\theta = 30^{\circ}, calculate the magnitude of the resultant force, in newtons.

Answer this when you sit the paper.

[2 marks]Resultant of coplanar forces

Coplanar forces of magnitudes 3 N, 4 N and 8 N act at a point as shown in the diagram. The 3 N force acts along the direction of j\mathbf{j}, the 4 N force acts along the direction of i\mathbf{i}, and the 8 N force acts at an angle θ\theta below the direction of −i-\mathbf{i}.

Given that θ=30∘\theta = 30^{\circ}, the resultant force is −2.928i−j-2.928\mathbf{i}-\mathbf{j} newtons. Find the angle, in degrees, between the resultant and the direction of −i-\mathbf{i}.

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Section b, Question 7

[2 marks]Kinematics and velocity-time graphs

A particle moves in a straight line. It starts with a velocity of 8 ms−1^{-1} and is subjected to a retardation of 32\dfrac{3}{2} ms−2^{-2} for 6 seconds.

Find the time, in seconds, at which the particle is momentarily at rest.

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[2 marks]Kinematics and velocity-time graphs

A particle moves in a straight line. It starts with a velocity of 8 ms−1^{-1} and is subjected to a retardation of 32\dfrac{3}{2} ms−2^{-2} for 6 seconds.

Find the displacement of the particle from its starting point after the 6 seconds, in metres.

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[3 marks]Kinematics and velocity-time graphs

A particle moves in a straight line. It starts with a velocity of 8 ms−1^{-1} and is subjected to a retardation of 32\dfrac{3}{2} ms−2^{-2} for 6 seconds.

Find the total distance travelled by the particle in the 6 seconds, in metres.

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